4x^2+8+4x^2-2x-2=540

Solution for 4x^2+8+4x^2-2x-2=540 equation:

4x^2+8+4x^2-2x-2=540

We move all terms to the left:

4x^2+8+4x^2-2x-2-(540)=0

We add all the numbers together, and all the variables

8x^2-2x-534=0

a = 8; b = -2; c = -534;
Δ = b2-4ac
Δ = -22-4·8·(-534)
Δ = 17092
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17092}=\sqrt{4*4273}=\sqrt{4}*\sqrt{4273}=2\sqrt{4273}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{4273}}{2*8}=\frac{2-2\sqrt{4273}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{4273}}{2*8}=\frac{2+2\sqrt{4273}}{16}
$